Edwin: “Do you know, when the Timpkinses married eighteen years ago Timpkins was three times as old as his wife, and to-day he is just twice as old as she?”
Angelina: “Then how old was Mrs. Timpkins on the wedding day?”
Can you answer Angelina’s question?
Let X = MR. TIMPKINS Let Y = MRS. TIMPKINS
18 years ago: (X-18)=3(Y-18) Today: X=2Y
Solving:
X-18=3Y-54
Substitute X=2Y
2Y-18=3Y-54 Y=36
Subract 18 from this (required by question) = MRS. TOMPKINS was 18 YEARS OLD on her wedding day. Good job kavita!
ans is 18..:)
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Discuss - 2 Comments
Let X = MR. TIMPKINS
Let Y = MRS. TIMPKINS
18 years ago: (X-18)=3(Y-18)
Today: X=2Y
Solving:
X-18=3Y-54
Substitute X=2Y
2Y-18=3Y-54
Y=36
Subract 18 from this (required by question) = MRS. TOMPKINS was 18 YEARS OLD on her wedding day. Good job kavita!
ans is 18..:)