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	<title>Durofy &#187; binomial theorem</title>
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		<title>The Derivative &amp; The Binomial Theorem</title>
		<link>http://www.durofy.com/mathematics/the-derivative-the-binomial-theorem/</link>
		<comments>http://www.durofy.com/mathematics/the-derivative-the-binomial-theorem/#comments</comments>
		<pubDate>Tue, 29 Jun 2010 19:52:37 +0000</pubDate>
		<dc:creator>Rishabh Dev</dc:creator>
				<category><![CDATA[Mathematics]]></category>
		<category><![CDATA[binomial theorem]]></category>
		<category><![CDATA[calculus]]></category>
		<category><![CDATA[calculus algebra]]></category>
		<category><![CDATA[mathematical beauty]]></category>

		<guid isPermaLink="false">http://zarrata.com/durofy/?p=273</guid>
		<description><![CDATA[If we observe closely, we find that the various branches of mathematics are all linked together in some way or the other. I show here one such observation. The binomial theorem can actually be expressed in terms of the derivatives of xn instead of the use of combinations. Lets start with the standard representation of [...]]]></description>
			<content:encoded><![CDATA[<p>If we observe closely, we find that the various branches of mathematics are all linked together in some way or the other. I show here one such observation. The binomial theorem can actually be expressed in terms of the derivatives of x<sup>n</sup> instead of the use of combinations. Lets start with the standard representation of the binomial theorm, <img src="http://latex.codecogs.com/gif.latex?large%20(x+a)^{n}=x^{n}+%20^{n}C_{1}ax^{n-1}+%20^{n}C_{2}a^{2}x^{n-2}+^{n}C_{3}a^{3}x^{n-3}+...^{n}C_{n}a^{n}" alt="" /> We could then rewrite this as a sum, <img src="http://latex.codecogs.com/gif.latex?huge%20(x+a)^{n}=sum_{0}^{n}^{n}C_{r}a^{r}x^{n-r}" alt="" /> Another way of writing the same thing would be, <img src="http://latex.codecogs.com/gif.latex?large%20(x+a)^{n}=x^{n}+nax^{n-1}+frac{n(n-1)}{1.2}a^{2}x^{n-2}+frac{n(n-1)(n-2)}{1.2.3}a^{3}x^{n-3}+...a^{n}" alt="" /> We observe here that the equation can be rewritten in terms of the derivatives of x<sup>n</sup>. The coefficient of a in the second terms is the first derivative of x<sup>n</sup>, similarily the coefficient of a<sup>2</sup>/2! in the second term is the second derivative of x... Lets look at the last term of the expansion, The coefficient of x<sup>n</sup>/n! should now be the n<sup>th</sup> derivative of x<sup>n</sup>. Which is very true... The following simple relation holds for all n... <img src="http://latex.codecogs.com/gif.latex?large%20frac{mathrm{d}%20}{mathrm{d}%20x}^{n}(x^{n})=n!" alt="" /> Hence, the binomial expansion can now be written in terms of derivatives! We have, <img src="http://latex.codecogs.com/gif.latex?large%20(x+a)^{n}=x^{n}+aD_{1}+frac{D_{2}}{2!}a^{2}+frac{D_{3}}{3!}a^{3}...frac{D_{n}}{n!}a^{n}" alt="" /> <em>where D<sub>r</sub> represents the rth derivate of x<sup>n</sup>.</em> Hence, we can now write this as a sum, http://latex.codecogs.com/gif.latex?huge%20(x+a)^{n}=sum_{0}^{n}frac{D_{r}a^{r}}{r!} So, we now have the expansion in terms of combinations as well as in terms of derivatives! <img src="http://latex.codecogs.com/gif.latex?huge%20(x+a)^{n}=sum_{0}^{n}^{n}C_{r}a^{r}x^{n-r}=sum_{0}^{n}frac{D_{r}a^{r}}{r!}" alt="" /><sup>n</sup> instead of the use of combinations. Lets start with the standard representation of the binomial theorm, <img src="http://latex.codecogs.com/gif.latex?(x+a)^{n}=x^{n}+%20^{n}C_{1}ax^{n-1}+%20^{n}C_{2}a^{2}x^{n-2}+^{n}C_{3}a^{3}x^{n-3}+...^{n}C_{n}a^{n}" alt="" /> We could then rewrite this as a sum, <img src="http://latex.codecogs.com/gif.latex?\huge%20(x+a)^{n}=\sum_{0}^{n}^{n}C_{r}a^{r}x^{n-r}" alt="" /> Another way of writing the same thing would be, <img src="http://latex.codecogs.com/gif.latex?(x+a)^{n}=x^{n}+nax^{n-1}+\frac{n(n-1)}{1.2}a^{2}x^{n-2}+\frac{n(n-1)(n-2)}{1.2.3}a^{3}x^{n-3}+...a^{n}" alt="" /> We observe here that the equation can be rewritten in terms of the derivatives of x<sup>n</sup>. The coefficient of a in the second terms is the first derivative of x<sup>n</sup>, similarily the coefficient of a<sup>2</sup>/2! in the second term is the second derivative of x... Lets look at the last term of the expansion, The coefficient of x<sup>n</sup>/n! should now be the n<sup>th</sup> derivative of x<sup>n</sup>. Which is very true... The following simple relation holds for all n... <img src="http://latex.codecogs.com/gif.latex?\huge%20\frac{\mathrm{d}%20}{\mathrm{d}%20x}^{n}(x^{n})=n!" alt="" /> Hence, the binomial expansion can now be written in terms of derivatives! We have, <img src="http://latex.codecogs.com/gif.latex?\large%20(x+a)^{n}=x^{n}+aD_{1}+\frac{D_{2}}{2!}a^{2}+\frac{D_{3}}{3!}a^{3}...\frac{D_{n}}{n!}a^{n}" alt="" /> <em>where D<sub>r</sub> represents the rth derivate of x<sup>n</sup>.</em>Hence, we can now write this as a sum, <img src="http://latex.codecogs.com/gif.latex?\huge%20(x+a)^{n}=\sum_{0}^{n}\frac{D_{r}a^{r}}{r!}" alt="" /> Or as the sum, <img src="http://latex.codecogs.com/gif.latex?\huge%20(x+a)^{n}=\sum_{0}^{n}\frac{D_{r}x^{r}}{r!}" alt="" /> So, we now have the expansion in terms of combinations as well as in terms of derivatives! <img src="http://latex.codecogs.com/gif.latex?\huge%20(x+a)^{n}=\sum_{0}^{n}^{n}C_{r}a^{r}x^{n-r}=\sum_{0}^{n}\frac{D_{r}a^{r}}{r!}" alt="" /></p>
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